(1x-7)(x^2+3x-3)=0

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Solution for (1x-7)(x^2+3x-3)=0 equation:


Simplifying
(1x + -7)(x2 + 3x + -3) = 0

Reorder the terms:
(-7 + 1x)(x2 + 3x + -3) = 0

Reorder the terms:
(-7 + 1x)(-3 + 3x + x2) = 0

Multiply (-7 + 1x) * (-3 + 3x + x2)
(-7(-3 + 3x + x2) + 1x * (-3 + 3x + x2)) = 0
((-3 * -7 + 3x * -7 + x2 * -7) + 1x * (-3 + 3x + x2)) = 0
((21 + -21x + -7x2) + 1x * (-3 + 3x + x2)) = 0
(21 + -21x + -7x2 + (-3 * 1x + 3x * 1x + x2 * 1x)) = 0
(21 + -21x + -7x2 + (-3x + 3x2 + 1x3)) = 0

Reorder the terms:
(21 + -21x + -3x + -7x2 + 3x2 + 1x3) = 0

Combine like terms: -21x + -3x = -24x
(21 + -24x + -7x2 + 3x2 + 1x3) = 0

Combine like terms: -7x2 + 3x2 = -4x2
(21 + -24x + -4x2 + 1x3) = 0

Solving
21 + -24x + -4x2 + 1x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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